answer: 2 × 2 × 2 × 2 × 2 = 32
Step-by-step explanation:
Answer:
Its c
Step-by-step explanation:
I just had this question on a recap quiz I was working on I hope this helps
Answer:
Option B. Cosec θ = –5/3
Option C. Cot θ = 4/3
Option D. Cos θ = –4/5
Step-by-step explanation:
From the question given above, the following data were obtained:
Tan θ = 3/4
θ is in 3rd quadrant
Recall
Tan θ = Opposite / Adjacent
Tan θ = 3/4 = Opposite / Adjacent
Thus,
Opposite = 3
Adjacent = 4
Next, we shall determine the Hypothenus. This can be obtained as follow:
Opposite = 3
Adjacent = 4
Hypothenus =?
Hypo² = Opp² + Adj²
Hypo² = 3² + 4²
Hypo² = 9 + 16
Hypo² = 25
Take the square root of both side
Hypo = √25
Hypothenus = 5
Recall:
In the 3rd quadant, only Tan is positive.
Therefore,
Hypothenus = –5
Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:
Opposite = 3
Adjacent = 4
Hypothenus = –5
Sine θ = Opposite / Hypothenus
Sine θ = 3/–5
Sine θ = –3/5
Cos θ = Adjacent / Hypothenus
Cos θ = 4/–5
Cos θ = –4/5
Cot θ = 1/ Tan θ
Tan θ = 3/4
Cot θ = 1 ÷ 3/4
Invert
Cot θ = 1 × 4/3
Cot θ = 4/3
Cosec θ = 1/ Sine θ
Sine θ = –3/5
Cosec θ = 1 ÷ –3/5
Invert
Cosec θ = 1 × –5/3
Cosec θ = –5/3
SUMMARY
Sine θ = –3/5
Cos θ = –4/5
Tan θ = 3/4
Cot θ = 4/3
Cosec θ = –5/3
Therefore, option B, C and D gives the correct answer to the question.
Answer:
equaly likely
Step-by-step explanation:
Answer:
Therefore the required rule for the given table is
Step-by-step explanation:
Given :
Table values are
x y
6 -12
7 -14
8 -16
9 -18
10 -20
To Find :
The rule for above result = ?
Solution:
The Required Rule for the above Table is
For first case
Put x = 6 in the rule we get
as shown in the table
For second case
Put x = 7 in the rule we get
as shown in the table
For third case
Put x = 8 in the rule we get
as shown in the table
For fourth case
Put x = 9 in the rule we get
as shown in the table
For fifth case
Put x = 10 in the rule we get
as shown in the table
Therefore the required rule for the given table is
