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3 years ago

Find the general solution: y''-2y'-3y=-3te^(-t)

Mathematics

1 answer:

allsm [11]3 years ago

5 0

The answer i got was -3te with -t as an exponent

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Can someone help. Write a word problem about equal groups and act it out to solve

Alona [7]

Answer:

HOPE THAT MAY HELP YOU :)

Step-by-step explanation:

Equal groups are illustrations of using the same variable.

A word problem that uses equal group is:

Christopher traveled a distance of 5 miles yesterday; he traveled a distance of 4 miles earlier today. Calculate the total distance traveled

The only condition for equal groups is that:

The units or variable must be the same

For instance:

Add 5 miles and 4 miles ----- This represents distance

Remove 2 liters from 7 liters --- This represents volume

Add 5 hours and quarter of an hour -- This represents time

And so on.

5 0

2 years ago

A recipe for cookies requires 2/3 cup of butter.Rama wants to make 3/4 of the recipe.how many cups of butter does she need to us

notsponge [240]

1 recipe = 2/3 cup of butter.

3/4 recipe = 3/4 x 2/3 = 1/2 cup of butter

Answer: 1/2 cup of butter

5 0

3 years ago

Please help need the answer now!!

Korvikt [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago

A metric unit of length that is equal to one thousandth of a meter is.......

12345 [234]

The metric unit of length that is equal to one thousandth of a meter is a millimeter. 1 meter = 1000 millimeter

hope this helps

3 0

3 years ago

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