<span>B. The argument is invalid because the conclusion does not follow the premises. Hope this helps! :)
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Celeste is 30 and Beth is 25
let x be Celeste's age now then Beth is x - 5
next year they will be 1 year older
Celeste's age will be x + 1 and Beth will be x - 5 + 1 = x - 4
the sum of their ages is therefore
x + 1 + x - 4 = 57
2x - 3 = 57 ( add 3 to both sides )
2x = 60 ( divide both sides by 2 )
x = 30
Celeste is 30 and Beth is 30 - 5 = 25
Answer:
72 percent of the total houses are small
Step-by-step explanation:
The first step is to know the total apartments from the ratio: This is got by adding 18 + 7 = 25
The ratio of small apartments to regular ones is 18:7
To get the percentage that is small, we have to express the number of small houses when compared to the total available apartments. (<em>Note: not the regular ones) </em>as a percentage.
This will be (18/25) X 100 = 72%
Therefore, 72 percent of the total houses are small
Answer:
B
Step-by-step explanation:
The x value is increasing by 3 so the next number in the sequence would be 0.
The y value is decreasing by 1 so the missing value would be 1.
Answer:
![\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]](https://tex.z-dn.net/?f=%5CSigma_%7Bk%3D1%7D%5E%7Bn%7D%5B3%28%5Cfrac%7B10%7D%7B9%7D%20%29%5E%7Bk-1%7D%5D)
Step-by-step explanation:
A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.
The first term is denoted by a and the common ratio is denoted by r.
A geometric sequence has the form:
a, ar, ar², ar³, . . .
The nth term of a geometric sequence is 
Therefore the sum of the first n terms is:

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is: