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Irina-Kira [14]
3 years ago
9

Find the Greatest Common Factor (GCF) of 3 and 15?

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

1,15 ;-;

Step-by-step explanation:

hope this helps :D

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Carl went to the store to buy items for his party.He bought two packs for plates for $3.24 and a pack of cups for $5.70. He also
Andre45 [30]

3.24 + 5.70 + 6.17 = 15.11

20.00 - 15.11 = 5.11

He got 5.11$ of change back.

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Create your own real-world problem that uses either a two-step equation or two-step inequality to solve. Based on your real-worl
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Libby wants to make cookies for her whole class. There are 36 students in her class. The recipe Libby is going to use only makes 12 cookies. How many batches of cookies is Libby going to have to make to feed her whole class?
36/12
3 0
3 years ago
HELP! WILL GIVE BRANLIEST!
mars1129 [50]

Answer:

D

Step-by-step explanation:

This is your answer because first you have 3x10-6 and 2x1030 what you have to do is that first you multiply 3 x 2 equals to 6 then, 10 x 1 = 10 then you have to multiply 30 x 6 = 180 then you put it together and your answer is 6x10-180

Hope this helps :)

pls mark me brainlist

8 0
3 years ago
12 is 30% of what number?
Sladkaya [172]

Answer is provided in the image attached.

4 0
3 years ago
Plz help!
beks73 [17]

First, you need to find the derivative of this function.  This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.  

f'(x)=3x^2-3

Now, set this function equal to 0 to find x-values of the relative max and min.

0=3x^2-3

0=3(x^2-1)

0=3(x+1)(x-1)

x=-1, 1

To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each.  We will use -2, 0, 2.

f'(-2)=3(-2)^2-3=3(4)-3=12-3=9

f'(0)=3(0)^2-3=3(0)-3=0-3=-3

f'(2)=3(2)^2=3(4)-3=12-3=9

We examine the sign changes to determine whether it is a max or a min.  If the sign goes from + to -, then it is a maximum.  If it goes from - to +, it is a minimum.  Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.

To determine the values of the relative max and min, plug in the x-values to f(x).

f(-1)=(-1)^3-3(-1)+1=-1+3+1=3

f(1)=(1)^3-3(1)+1=1-3+1=-1

Hope this helps!!

7 0
4 years ago
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