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BlackZzzverrR [31]

3 years ago

14

Select one of the factors of x2y3 − 11x2y + 6y2 − 66

2 answers:

EleoNora [17]3 years ago

5 0

We try to factor by maybe grouping
experiment

(x²y³-11x²y)+(6y²-66)
factor
x²y(y²-11)+6(y²-11)
undistribute (y²-11) from each
(x²y+6)(y²-11)
we can force a factor out of the 2nd group in the form of a difference of 2 perfect squares
(x²y+6)(y-√11)(y+√11)
either of those 3 are factors

Aloiza [94]3 years ago

4 0

Answer:

(x²y+6)(y-√11)(y+√11)

Step-by-step explanation:

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A ribbon measure 4.5 meters express length to millimeters<br>

GREYUIT [131]

Answer:

4500 millimeters

Step-by-step explanation:

6 0

2 years ago

P(x)=6/7x+4 What is P(42)

Natali5045456 [20]

40

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4 0

2 years ago

Which expression is a difference of cubes?

Tanzania [10]

Answer:

Option 4 is correct.

Step-by-step explanation:

Given the following options

we have to choose the difference of cubes.

Option 1:

$9w^{33}-y^{12}$

$9(w^{11})^{3}-(y^4)^3$

which is not the difference of cubes

Option 2:

$18p^{15}-q^{21}$

$18(p^5)^3-(q^7)^3$

which is not the difference of cubes

Option 3:

$36a^{22}-b^{16}$

$(6a^{11})^2-(b^8)^2$

which is the difference of square

Option 4:

$64c^{15}-a^{27}$

$(4c^5)^3-(a^9)^3$

which is the difference of cubes.

8 0

2 years ago

GEOMETRY!!!!!!!!!!!!!

Rina8888 [55]

(1,F)(2,C)(3,H)(4,A)(5,G)(6,G)(7,D)(8,B)(9,E)

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4 0

3 years ago

A collection of five coins has a value of $1 and consists of dimes and

DENIUS [597]

For this case we propose a system of equations. We have to:

x: Let the variable that represents the number of dimes

y: Let the variable that represents the number of quaters

We know that:

One dime equals 10 cents, $0.10

A quater equals 0.25 cents, $0.25

According to the statement we have:

$x + y = 5\\0.10x + 0.25y = 1$

We multiply the first equation by -0.10:

$-0.10x-0.10y = -0.5$

We have the following equivalent system:

$-0.10x-0.10y = -0.5\\0.10x + 0.25y = 1$

We add the equations:

$-0.10x + 0.10x-010y + 0.25y = -0.5 + 1\\0.15y = 0.5\\y = \frac {0.5}{0.15}\\y = 3.33$

Approximately 3 quater coins

$x = 5-y = 5-3 = 2$

And two dimes

Answer:

3 quater

2 dimes

4 0

2 years ago