4 years ago

Select one of the factors of x2y3 − 11x2y + 6y2 − 66

2 answers:

5 0

We try to factor by maybe grouping
experiment

(x²y³-11x²y)+(6y²-66)
factor
x²y(y²-11)+6(y²-11)
undistribute (y²-11) from each
(x²y+6)(y²-11)
we can force a factor out of the 2nd group in the form of a difference of 2 perfect squares
(x²y+6)(y-√11)(y+√11)
either of those 3 are factors

Aloiza [94]4 years ago

4 0

Answer:

(x²y+6)(y-√11)(y+√11)

Step-by-step explanation:

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