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Schach [20]
3 years ago
8

How do I solve this?

Mathematics
1 answer:
daser333 [38]3 years ago
3 0
First, you must distribute the negative sign(otherwise considered a negative one). This gives you x - 4x + 7 = 5x - x - 21.
Then, simplify any like terms you can: -3x + 7 = 4x - 21.
Simplify this even further: 28 = 7x
The final answer is x = 4
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Find the inverse of y=ln2x
never [62]

Answer:

The exponential function, exp : R → (0,∞), is the inverse of the natural logarithm, that is, exp(x) = y ⇔ x = ln(y). Remark: Since ln(1) = 0, then exp(0) = 1. Since ln(e) = 1, then exp(1) = e.

Step-by-step explanation:The exponential function, exp : R → (0,∞), is the inverse of the natural logarithm, that is, exp(x) = y ⇔ x = ln(y). Remark: Since ln(1) = 0, then exp(0) = 1. Since ln(e) = 1, then exp(1) = e.

4 0
3 years ago
What is a expression that is equivalent to 4(6x+ x)
lilavasa [31]
24x+4x , I’m pretty sure
3 0
3 years ago
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Round $60.55 to nearest dollar
eimsori [14]
it would be $61 because 5 rounds up
5 0
3 years ago
Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
Salsk061 [2.6K]

Answer: In June 2097

Step-by-step explanation:

According to the model, to find how many years t should take for  P(t)=21100 we must solve the equation  0.9t^2+6t+14000=21100. Substracting 21100 from both sides, this equation is equivalent to 0.9t^2+6t-7100=0.

Using the quadratic formula, the solutions are t_1= \frac{-6-\sqrt{6^2 -4*0.9*(-7100)}}{2*0.9}=-92.21 and t_2=\frac{-6+\sqrt{6^2 -4*0.9*(-7100)}}{2*0.9}=85.54. The solution t_1=-92.21 can be neglected as the time t is a nonnegative number, therefore t=t_2=85.54.

The value of t is approximately 85 and a half years and the initial time of this model is the January 1, 2012. Adding 85 years to the initial time gives the date  January 2097, and finally adding the remaining half year (six months) we conclude that the date is June 2097.

6 0
3 years ago
Danielle makes the claim that when the polynomial x^2-3x-10 is divided by x-5, the remainder is 0. Use what you have learned abo
Mumz [18]

Answer:

<h3>Daniel is correct</h3>

Step-by-step explanation:

Given the polynomial P(x) = x^2-3x-10

To check that the remainder is zero if divided by x - 5, we will first have to equate x - 5 to zero and get x;

x - 5 = 0

x = 5

Then find P(5)

P(5) = 5^2 - 3(5) - 10

P(5) = 25 - 15 - 10

P(5) = 25-25

P(5) = 0

<em>This shows that x - 5 is a factor of the polynomial since P(5) gave us zero according to the factor theorem</em>

7 0
3 years ago
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