The weight of a ship is frequently called its "displacement" since that's the weight of the water that it uproots. It'll drift when it uproots a volume of water whose weight is break even with the weight of the ship -- this can be the buoyant drive given by the water. New water in an inland lake features a littler density than that of ocean water. Hence, a larger volume of new water is vital to supply the same weight or buoyant force. This implies the ship will ride lower in an inland lake and will ride higher within the sea.
<h3>what is buoyant force?</h3>
When an object is set in a liquid, the liquid applies an upward force we call the buoyant force. The buoyant force comes from the weight applied to the question by the liquid. Since the weight increments as the profundity increments, the weight on the foot of an object is continuously bigger than the force on the best - consequently the net upward force. The buoyant force is present whether the question coasts or sinks.
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Answer:
new atmospheric pressure is 0.9838 × 
Pa
Explanation:
given data
height = 21.6 mm = 0.0216 m
Normal atmospheric pressure = 1.013 ✕ 10^5 Pa
density of mercury = 13.6 g/cm³
to find out
atmospheric pressure
solution
we find first height of mercury when normal pressure that is
pressure p = ρ×g×h
put here value
1.013 × = 13.6 × 10³ × 9.81 × h
h = 0.759 m
so change in height Δh = 0.759 - 0.0216
new height H = 0.7374 m
so new pressure = ρ×g×H
put here value
new pressure = 13.6 × 10³ × 9.81 × 0.7374
atmospheric pressure = 98380.9584
so new atmospheric pressure is 0.9838 × Pa
Answer:
5.66 × 10⁻²³ m/s
Explanation:
If i assume i can jump as high as h = 2 m, my initial velocity is gotten from v² = u² + 2gh. Since my final velocity v = 0, u = √2gh = √(2 × 9.8 × 2) = √39.2 m/s = 6.26 m/s.
Since initial momentum = final momentum,
mv₁ + MV₁ = mv₂ + MV₂ where m, M, v₁, V₁, v₂ and V₂ are my mass, mass of earth, my initial velocity, earth's initial velocity, my final velocity and earth's final velocity respectively.
My mass m = 54 kg, M = 5.972 × 10²⁴ kg, v₁ = 6.26 m/s, V₁ = 0, v₂ = 0 and V₂ = ?
So mv₁ + M × 0 = m × 0 + MV₂
mv₁ = MV₂
V₂ = mv₁/M = 54kg × 6.26 m/s/5.972 × 10²⁴ kg = 338.093/5.972 × 10²⁴ = 56.61 × 10⁻²⁴ m/s = 5.661 × 10⁻²³ m/s ≅ 5.66 × 10⁻²³ m/s
Answer:
Explanation:
Given
Distance between two balls is 
mass of first ball 
mass of second ball 
Gravitational force between two forces is given by
Substituting values
where G=gravitational constant
