Not all forms of radiation is safe for humans
The momentum of the red cart before the collision is 0.2 kgm/s and the blue cart is 0.
The momentum of the red cart after the collision is 0.05 kgm/s and the blue cart is 0.15 kgm/s.
The change in momentum of the system of the carts is 0.
<h3>
Initial momentum of the carts before collision</h3>
The momentum of the carts before the collision is calculated as follows;
P(red) = 0.5 kg x 0.4 m/s = 0.2 kgm/s
P(blue) = 1.5 x 0 = 0
<h3>Momentum of the carts after collision</h3>
The momentum of the carts after the collision is calculated as follows;
P(red) = 0.5 x 0.1 = 0.05 kgm/s
P(blue) = 1.5 0.1 = 0.15 kgm/s
<h3>Change in momentum of the carts</h3>
ΔP = (0.05 + 0.15) - (0.2)
ΔP = 0
Learn more about momentum here: brainly.com/question/7538238
M/s^2 since acceleration is velocity/time=m/s/s=m/s^2
Yeah I’m guessing because I need help also
Answer:
only E is true
Explanation:
A) to find out if it would fall 4x as fast by 2x the time we can look at the formula for free fall:
for free fall the Y = g where Y is the distance fallen, g is gravity and t is time
so since the rate at which an object falls is the same (gravity stays the same) it will not fall faster with any alteration
B) An object would fall half the distance if you double the time
here we may need to check with an example:
lets say we fall for 2 seconds in the first and 4 in the second:
Y= 1/2 (9.8) (2)^2 gives 19.6m fallen
Y= 1/2 (9.8) (4)^2 gives 78.4m fallen
from this we can see that doubling the time does not half the distance
C) all objects fall at the same rate no matter their mass so this statement is false
D) from the example above we see again that doubling time does not double the distance
E) this statement is true