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Fantom [35]
3 years ago
14

A cylinder is a radius of 8cm and a volume of 800cm³ calculate it's height and total surface area

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

3.98 cm, 602.18 cm²

Step-by-step explanation:

<u>Given:</u>

  • r= 8 cm
  • V= 800 cm³

<u>To find:</u>

  • h = ?
  • S = ?

<u>Solution:</u>

  • V = πr²h
  • h = V/πr² = 800/(π8²) = 3.98 cm
  • S = 2πr (r+h) = 16π(8+3.98) = 602.18 cm²
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For the sequence below, explain the pattern in words.<br> 14. 11. 8. 5....
AVprozaik [17]

Answer:

you subtract the number by 3

Step-by-step explanation:

the pattern is x-3 so the pattern is subtracting the number by 3 every time

6 0
2 years ago
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RoseWind [281]

Answer:

It's the one under the one you have selected.

Step-by-step explanation:

7:2

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56:16

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The GCF of an odd number and an even number will always be even
Gelneren [198K]
This is false for example, the GCF of 13 and 26 is 13, an odd number.
8 0
3 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
Pls helps fast!!
Aleks [24]

Answer:

Option B is correct.

Step-by-step explanation:

We have given a triangle ABC and EDC please look at the figure

We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles

And ∠ACB=∠DCE are vertically opposite angles hence, equal

So, by AA similarity postulate the above to triangles are similar

ΔABC \sim ΔEDC

Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5

NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE

And m∠1 = m∠5 corresponds to m∠EAB=m∠AED

3 0
3 years ago
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