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4 years ago

Please help! i need to find the mean

Mathematics

1 answer:

irina1246 [14]4 years ago

7 0

Answer:

Step-by-step explanation:

$\overline x =\dfrac{-3\cdot4+(-2)\cdot2+3\cdot1+4\cdot1+6\cdot4+8\cdot7}{4+2+1+1+4+7}\\\\\\\overline x =\dfrac{-12-4+3+4+24+56}{19}\\\\\\\overline x =\dfrac{71}{19}=3.7368421....\approx3.74$

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Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se

sesenic [268]

Answer:

$Log_5 12=1.54$

Step-by-step explanation:

We are given that

$Log_5 12$

We have to find the value of given logarithms by using change-base formula

Base-change formula:

$log_a b=\frac{Log_x b}{Log_x a}$

Where x=New base

Using the formula then, we get

$Log_5 12=\frac{log_{10} 12}{log_{10} 5}$

Substitute the values $log_{10}12=1.079, log_{10}5=0.699$

Then,we get

$Log_5 12=\frac{1.079}{0.699}$

$Log_5 12=1.54$

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3 years ago

Which point is on a line that passes through point R and is perpendicular to line PQ?

aliya0001 [1]

Your answer would be (-4,-8)

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3 years ago

Read 2 more answers

I need help asap

Zielflug [23.3K]

Answer:

Option 4

Step-by-step explanation:

So formula of voulme of the cube is a³

We have the side length is 6x

So sub the value in formula we get 216x³

3 0

3 years ago

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Find the slope of the line through each pair of points.<br><br> 11) (-20, -4), (-12, -10)

antoniya [11.8K]

Answer:

slope= -6/8 or -3/4

Step-by-step explanation:

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3 0

2 years ago

How do I solve for a

qwelly [4]

Answer:

using the pythagoras theorem the answer is a=3

Step-by-step explanation:

basically in a right angled triangle a² + b² equals c². in this equation c is the number on the hypotenuse (the line opposite the right angle)

and 4 could be a or b it doesnt make a difference so I'll call it b.

because we have c² and b² we work backwards like this:

${5}^{2} - {4}^{2} = {a}^{2}$

${5}^{2} - {4}^{2} = 25 - 16 = 9$

because 9 is a², we must find the square root to find <em>a</em>

$\sqrt{9 } = 3$

so a equals 3

3 0

3 years ago