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2 years ago

Look at the image, read, and choose the option with the correct answer.

Mathematics

1 answer:

scoundrel [369]2 years ago

6 0

The lady who is neither old nor gray, who has long brown hair and has a son with brown hair and a daughter with red hair is _Clair_.

<h3>How to conjugate a verb in spanish?</h3>

Verbs are divided into 3 groups called conjugations, that are identified by ending the verbs in their unconjugated infinitive form.

Each of the conjugations has its own inflections, but usually the second and third are very similar.

The lady who is neither old nor gray, who has long brown hair and has a son with brown hair and a daughter with red hair is _Clair_.

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Help me please and thank you

AURORKA [14]

Answer:

Step-by-step explanation:

You just count the dots and check the tables.

4 0

2 years ago

The mean annual premium for automobile insurance in the United States is $1503 (Insure website, March 6, 2014). Being from Penns

romanna [79]

Answer:

If we compare the p value and the significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean annual premium in Pennsylvania is significantly lower than the national mean annual premium of 1503 at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=1440$ represent the mean annual premium value for the sample

$s=165$ represent the sample standard deviation for the sample

$n=25$ sample size

$\mu_o =1503$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean annual premium in Pennsylvania is lower than the national mean annual premium, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1503$

Alternative hypothesis: $\mu < 1503$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1440-1503}{\frac{165}{\sqrt{25}}}=-1.909$