2 years ago

Which of the following relations is a function?

Mathematics

1 answer:

Agata [3.3K]2 years ago

5 0

Answer:

Step-by-step explanation:

Because in D, there no x-value that are repeating in the list.

For example A, the value 8 and -8 are being repeated twice, which makes this relation not a fuction.

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It is given that y is inversely proportional to the square of x and that y=48 when x=<img src="https://tex.z-dn.net/?f=%5Cfrac%7

Anna [14]

Answer:

$a. y = 12\times \frac{1}{x^2} \\b. x = 2 , when \ y =3$

Step-by-step explanation:

$y \ is\ inversely \ proportional \ to \ square \ of \ x \ means , y \ \alpha \ \frac{1}{x^2}$

$Therefore, y = k \times \frac{1}{x^2}$

Given y = 48, x = 1/2. We will find k.

$y = k \times \frac{1}{x^2}\\\\48 = k \times \frac{1}{\frac{1}{4}}}\\\\k = 48 \times \frac{1}{4} =12$

Find x.

$y = k \times \frac{1}{x^2} \\\\3 = 12 \times \frac{1}{x^2}\\\\\frac{3}{12} = \frac{1}{x^2}\\\\x^2 = \frac{12}{3}\\\\x^2 = 4 \\\\x = 2$

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Answer:

Step-by-step explanation:

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