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serious [3.7K]
3 years ago
13

On an uphill hike, Ted climbs at a rate of 3 miles an hour. Going down, he runs at a rate of 5 miles an hour. If it takes him 40

minutes longer to climb up than run down, what is the total length of Ted's hike?
Mathematics
2 answers:
Hitman42 [59]3 years ago
4 0

So the other guy has the right work but at the end he messed up. The real answer is 10 miles.

telo118 [61]3 years ago
3 0

It takes 40 minutes more going up or 40/60 = 0.67 hours more.

Let us say that:

t = the time required for him running down

t + 0.67 = time required for him running up

 

Since the distance of running up and down must be equal therefore:

(3 miles / hr) * (t + 0.67) = (5 miles / h) * t

3 t + 2.01 = 5 t

2 t = 2.01

t = 1.005 hr

 

So the total length of the hike is:

length = 2 * (5 miles / hr) * (1.005 hr)

<span>length = 10.05 miles</span>

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vichka [17]
1= 130 yards

2= 55 yards

3= 25
4 0
3 years ago
Five times the sum of 3 and twice some numbers is 70. What is the number?
Anna11 [10]
Let x represent some number
Sum of 3 and twice some number = 3 +2x
Five times the sum of 3 and twice some number: 5(3+2x)

5(3+2x)=70
15+10x=70
Subtract 15 from both sides to have 10x by itself
10x=55
Divide 10 on both sides to get x by itself
x=55/10
x=5.5

Hope this helped
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Vitek1552 [10]

Is this the whole equation?

Step-by-step explanation:

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3 years ago
How to convert m into mm​
ArbitrLikvidat [17]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Find the area of the shaded region. Express your answer in terms of pi
Likurg_2 [28]

Area of the shaded region is 540 – 65.25π.    

Solution:

Length of the rectangle = 12 + 9 + 6 + 3 = 30 in

Width of the rectangle = 18 in

Radius of the larger circle (r_1) = 12 ÷ 2 = 6 in

Radius of the medium circle (r_2) = 9 ÷ 2 = 4.5 in

Radius of the smaller circle (r_3) = 6 ÷ 2 = 3 in

Area of the shaded region = Area of the rectangle – Area of the larger circle – Area of the medium circle – Area of the smaller circle

                                   =l\times b-\pi r_1^2-\pi r_2^2-\pi r_3^2

                                   =30\times 18-\pi \times 6^2-\pi \times (4.5)^2-\pi \times 3^2

                                   =540-36\pi-20.25\pi-9\pi

                                   =540-65.25\pi

Area of the shaded region is 540 – 65.25π.    

4 0
3 years ago
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