4. A square field had 5 m added to its length and 2 m added

Mathematics

1 answer:

Zepler [3.9K]2 years ago

6 0

The length of side of the original field is 8 meters

Step-by-step explanation:

Let x be the original side of the square field

Then the new sides will be

x+2 and x+5

And

Area = 130

The area is given by:

$A=side*side$

Putting the values in the formula

$130= (x+2)(x+5)\\(x+2)(x+5) = 130\\x^2+7x+10 = 130\\x^2+7x+10-130 = 0\\x^2+7x-120 = 0\\x^2+15x-8x-120 = 0\\x(x+15)-8(x+15)=0\\(x-8)(x+15) = 0$

Either x-8 = 0 => x=8

Or x+15 = 0 => x=-15

As the measurement of length cannot be negative, so only positive values

So,

The length of side of the original field is 8 meters

Keywords: Factorization, Linear factors

Learn more about factorization at:

#LearnwithBrainly

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Please help asap (:

Korolek [52]

For this case we first define the variable:
x = number of terms.
The equation that models the problem is:
f (x) = 3.4 - 0.6x
We have then that the first four terms are:
x = 1
f (1) = 3.4 - 0.6 (1) = 3.4 - 0.6 = 2.8
x = 2
f (2) = 3.4 - 0.6 (2) = 3.4 - 1.2 = 2.2
x = 3
f (3) = 3.4 - 0.6 (3) = 3.4 - 1.8 = 1.6
x = 4
f (4) = 3.4 - 0.6 (4) = 3.4 - 2.4 = 1
Answer:
The rule for the sequence is:
f (x) = 3.4 - 0.6x
option 1

7 0

3 years ago

Read 2 more answers

5/9 × 8/11 what is the answer

nikitadnepr [17]

Answer:

$\frac{5}{9} \times \frac{8}{11} = \frac{5 \times 8}{9 \times 11} = \frac{40}{99} = 0.4040$