Answer:
6 address lines
Explanation:
The computation of the number of address lines needed is shown below:
Given that
Total memory = 64MB
= 
=
Also we know that in 1MB RAM the number of chips is 6
So, the number of address lines is 
i..e 26 address lines
And, the size of one chip is equivalent to 1 MB i.e. 
For a single 1MB chips of RAM, the number of address lines is
Therefore 6 address lines needed
Answer:
See explaination
Explanation:
#include <stdio.h>
#include <stdlib.h>
int main()
{
FILE * file_object;
char file_name[100];
char ch;
int characters=0, words=0;
printf("Enter source file name: ");
scanf("%s", file_name); //asking user to enter the file name
file_object = fopen(file_name, "r"); //open file in read mode
if (file_object == NULL)
{
printf("\nUnable to open file.file not exist\n"); //check if the file is present or not
}
while ((ch = fgetc(file_object)) != EOF) //read each character till the end of the file
{
if (ch == ' ' || ch == '\t' || ch == '\n' || ch == '\0') //if character is space or tab or new line or null character increment word count
words++;
else
characters++; //else increment character count this assures that there is no spaces count
}
printf("The file story.txt has the following Statistics:\n"); //finally print the final statistics
if (characters > 0)
{
printf("Words: %d\n", words+1); //for last word purpose just increment the count of words
printf("Characters (no spaces): %d\n", characters);
}
fclose(file_object); //close the file object
return 0;
}
The answer to your question is,
Server virtualization
-Mabel <3
Answer:
Hey whats up
Explanation:
Count me in chief! I love when fellow user give out mighty points
Answer: you can say or talket to them why or how
Explanation:
