Which IEEE standards define Wi-Fi technology?

¿Cuál es la potencia de una lámpara de incandescencia que se conecta a la red de 220 V, sabiendo que tiene una resistencia de 50

Juliette [100K]

Answer:

<u>1,000W</u> (rounded to one significant figure)

Explanation:

I will answer in English.

The question is:

<em>What is the power of a filament lamp that connects to the 220 V network, knowing that it has a resistance of 50 ohms?</em>

<em />

<h2>Solution</h2>

<em />

<em>Power</em>, <em>voltage</em>, <em>resistance</em>, and current, are related by either of the following equations:

P = V × I

P = R × I²

P = V² / R

Where:

P is power in watts (W)

R is resistance in ohms (Ω)

V is voltage in volts (V), and

I is current in amperes (A)

Since you know the voltage (<em>220V</em>) and the resistance (<em>50Ω</em>), you can use the last equation:

P = V² / R

P = (220v)² / (50Ω)

P = 968 W

Since the magnitude 50Ω has one significant figure, your answer should be rounded to one significant figure. That is <u>1,000W.</u>

7 0

2 years ago

Look at the options below. Which one is a simulation?

Elena-2011 [213]

Im going to guess the 2nd one.

The 1st one just shows how trees can make ____ and then goes to water, the sun, then the rain but it CAN be used as one.

The 2nd one seems to explain the best it can show about weather, water, landforms, the sun, and seems like a better one to choose.

5 0

2 years ago

What changes do you need to make to the algorithm to take as first input the numbers to be compared

Alenkinab [10]

Answer:

Explanation:

The constant function is useful in algorithm analysis, because it characterizes the number of steps needed to do a basic operation on a computer, like adding two numbers, assigning a value to some variable, or comparing two numbers. Executing one instruction a fixed number of times also needs constant time only.

6 0

2 years ago

Pls help!!

alexira [117]

Answer:

4.24

Explanation:

First you find the mean of the data set, which is 7. Then to find standard deviation you have to follow the formula which tells you to subtract the mean from each number under the square root : √(2 - 7)^2 + (9 - 7)^2 + (10 - 7)^2 + (4 - 7)^2 + (8 - 7)^2 + (4 - 7)^2 + (12 - 7). Once you solve the parenthesis you square it, once you square it the negatives won't matter. That will leave you with this : √(25 + 4 + 9 + 9 + 25). The formula tells you to find the sum of those numbers (which is 72) then subtract one from how many numbers there are, 5 - 1 = 4, and divide your sum by that number. So 72 / 4 = 18. Then you find the square root of 18 and that becomes your answer.

7 0

1 year ago

Suppose we compute a depth-first search tree rooted at u and obtain a tree t that includes all nodes of g.

Temka [501]

G is a tree, per node has a special path from the root. So, both BFS and DFS have the exact tree, and the tree is the exact as G.

An algorithm for navigating or examining tree or graph data structures is called depth-first search. The algorithm moves as far as it can along each branch before turning around, starting at the root node.

The breadth-first search strategy can be used to look for a node in a tree data structure that has a specific property. Before moving on to the nodes at the next depth level, it begins at the root of the tree and investigates every node there.

First, we reveal that G exists a tree when both BFS-tree and DFS-tree are exact.

If G and T are not exact, then there should exist a border e(u, v) in G, that does not belong to T.

In such a case:

- in the DFS tree, one of u or v, should be a prototype of the other.

- in the BFS tree, u and v can differ by only one level.

Since, both DFS-tree and BFS-tree are the very tree T,

it follows that one of u and v should be a prototype of the other and they can discuss by only one party.

This means that the border joining them must be in T.

So, there can not be any limits in G which are not in T.

In the two-part of evidence:

Since G is a tree, per node has a special path from the root. So, both BFS and DFS have the exact tree, and the tree is the exact as G.

The complete question is:

We have a connected graph G = (V, E), and a specific vertex u ∈ V.

Suppose we compute a depth-first search tree rooted at u, and obtain a tree T that includes all nodes of G.

Suppose we then compute a breadth-first search tree rooted at u, and obtain the same tree T.

Prove that G = T. (In other words, if T is both a depth-first search tree and a breadth-first search tree rooted at u, then G cannot contain any edges that do not belong to T.)

To learn more about DFS and BFS, refer to:

brainly.com/question/13014003

#SPJ4

5 0

1 year ago