<span>The area of the square is d^2. The area of the circle sandbox is πr^2=πd^2/4. So the area of play area only is equal to square area minus circle area which is d^2-πd^2/4.</span>
Answer: 16 units
Step-by-step explanation: adding the perimeter sides to get the perimeter of triangle ABC would be 4.1+6.1+5.8 = 16
Answer:
5–3 = 2
8–5 = 3
12–8 = 4
17–12 = 5
x-17 should be 6, hence x = 6+17 = 23.
Step-by-step explanation:
The correct answer is: [D]: " <span>x-int : 1 , y-int: 0.5 " .
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Note:
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The "x-intercept" refers to the point(s) at which the the graph of a function (which is a "line", in this case) cross(es) the "y-axis".
In other words, what is (are) the point(s) of the graph at which "x = 0<span>" ?
</span>
By examining the graph, we see that when " x = 0" ; y is equal to: "1<span>" .
</span>
So; the "x-intercept" is at point: "(0, 1)" ; or, we can simply say that the
"x-intercept" is: "1" .
_________________________________________________________</span> Note:
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The "y-intercept" refers to the point(s) at which the the graph of a function (which is a line, in this case) cross(es) the "x-axis".
In other words, what is (are) the point(s) of the graph at which " y = 0 <span>" ?
</span>
By examining the graph, we see that when " y = 0 " ; x is equal to: "0.5<span>" .
</span>
So; the "x-intercept" is at point: "(0.5, 0)" ; or, we can simply say that the
"y-intercept" is: "0.5 " .<span>
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This would correspond to:<span>
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Answer choice: [D]: </span>" x-int: 1 , y-int: 0.5 " .
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{that is; The "x-intercept" is: "0" ; and the "y-intercept" is: "0.5 ".} .
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