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dexar [7]
3 years ago
5

A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma

ller number. Which equations represent the situation?

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

A.

Step-by-step explanation:

<em>NOTE: The "larger number" will be referred to as y, and the "smaller number" will be referred to as x.</em>

"A number, y, is equal to twice the sum of a smaller number and 3."

This tells us that we must add our smaller number (x) to 3 within parantheses and then multiply the entire term (x+3) by 2.

y=2(x+3)

"The larger number is also equal to 5 more than 3 times the smaller number."

This tells us that we must multiply 3 against our smaller number (x) and add 5 to it.

y=3x+5

Now, to find your answer, we can put the equations in the same form as the answer choices so as to find an equivalent equation. Lets start with the first equation.

This form calls for us to have our x term first, then our y term, then our constant.

y=2(x+3)\\y=2x+6\\-2x+y=6

Now that we've gotten the equation in that form, we can see that our answer choices hold that our leading co-efficient must be positive, which we can adjust for by dividing both sides by -1.

-2x+y=6\\2x-y=-6

This makes the only possible answer choices (A) and (C).

Now, lets do our second equation. The recipe calls for the same form, again with a positive leading coefficient.

y=3x+5\\-3x+y=5\\3x-y=-5

This is only represented by choices (A) and (B).

Therefore, answer choice (A) is the only one which represents both equations.

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Roman55 [17]
I hoped this helped or something

5 0
2 years ago
Please help. Look at screenshot
Citrus2011 [14]

Answer:

a.

<u>Increasing:</u>

x < 0

x > 2

<u>Decreasing:</u>

0 < x < 2

b.

-1 < x < 2

x > 2

c.

x < -1

Step-by-step explanation:

a.

Function is increasing when it is going up as we go rightward

Function is decreasing when it is going down as we go rightward

We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).

So,

<u>Increasing:</u>

x < 0

x > 2

The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:

<u>Decreasing:</u>

0 < x < 2

b.

When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].

Looking at the graph, it is

from -1 to 2 (x axis)

and 2 to positive infinity

We can write:

-1 < x < 2

x > 2

c.

Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.

This will be the other intervals than the ones we mentioned above in part (b).

Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:

x < -1

4 0
3 years ago
Please help just tell if the answers are reasonable or not DONT find the real correct answer.
enot [183]

Answer:

annna

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
R−5r−6s+8s−15 what is the answer for this equation
weeeeeb [17]

Step-by-step explanation:

r-5r-6s+8s-15

-4r+2s-15

= 2s-4r-15

4 0
2 years ago
The given line passes through the points (-4,-3) and (4,
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

first we gotta find the slope of the first line

(-4,-3),(4,1)

slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2

so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :

1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope

y - y1 = m(x - x1)

slope = -2

(-4,3)...x1 = -4 and y1 = 3

now sub

y - 3 = -2(x - (-4) =

y - 3 = -2(x + 4) <=====

6 0
3 years ago
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