Question

Please help (the question is in the attached image)

Answer 1

Answer:

a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm

b.

sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.

than AT=BT

3x+6=42-x

3x+x=42-6

x=36/4=9

AT=3×9+6=27+6=33

c.

since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.

EH=GH

5y+10=28-y

6y=28-10

y=18/6=3