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Hitman42 [59]
4 years ago
5

You roll a six-sided die twice. What is the probability of rolling a 2 and then an odd number?

Mathematics
1 answer:
-BARSIC- [3]4 years ago
8 0

Answer:

C) 1/ 12

Step-by-step explanation:

for a fair 6-sided die, for each independent roll, the possible number of outcomes is 1,2,3,4,5,6. I.e there are 6 possible outcomes

Also realize that there is only one "2" out of the 6 possible outcomes.

hence P(roll 2)  = 1/6

Similarly, there are 3 odd numbers (i.e 1, 3, 5) out of the 6 possible outcomes

hence P(roll odd number) = 3 /6 = 1/2

P (roll 2 on first roll then odd number on second roll)

= P(roll 2) x P(roll odd number)

= 1/6 x 1/2

= 1/12

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emmasim [6.3K]

Answer:

C

Step-by-step explanation:

✔️First, solve for r:

r/2 ≤ 3

Multiply both sides by 2

r/2 × 2 ≤ 3 × 2

r ≤ 6

This implies that possible value of r is equal to 6 or less than 6.

Graphing this on a number line, the line with a shaded circle, indicating that 6 is included, starts at 6 and points to the left.

This indicates that value of r ranges from 6 and below.

The graph is C.

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3 years ago
The gcf of 23 and 46
Sergeu [11.5K]
The cc’d between 23 and 46 is 23
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3 years ago
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crimeas [40]
Your answer is going to be B.3! Hope it helps
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4 years ago
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Solve with work <br><br>24.32 ÷ 6.4​
Rina8888 [55]

Answer:

3.8 is the answer plus using a calculator could have helped you too

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3 years ago
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Ksivusya [100]

Answer:

Option (1)

Step-by-step explanation:

Coordinates of the vertices of a quadrilateral WXYZ drawn in the figure are,

W(-1, 4), X(2, 2), Y(0, -1), Z(-3, 1)

Length of a segment having ends as (x_1, y_1) and (x_2, y_2) is represented by,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of WX = \sqrt{(-1-2)^2+(4-2)^2}

                       = \sqrt{9+4}

                       = \sqrt{13}

Length of XY = \sqrt{(2-0)^2+(2+1)^2}

                      = \sqrt{13}

Length of YZ = \sqrt{(0+3)^2+(-1-1)^2}

                      = \sqrt{13}

Length of ZW = \sqrt{(-1+3)^2+(4-1)^2}

                      = \sqrt{13}

Slope of side WX (m_1) = \frac{y_2-y_1}{x_2-x_1}

                                  = \frac{4-2}{-1-2}

                                  = -\frac{2}{3}

Slope of side XY (m_2) = \frac{2+1}{2-0}

                                    = \frac{3}{2}

By the property of perpendicular lines,

m_1\times m_2=-1

(-\frac{2}{3})(\frac{3}{2})=-1

therefore, WX and XY are perpendicular.

Slope of YZ (m_3) = \frac{-1-1}{0+3}=-\frac{2}{3}

m_2\times m_3=(\frac{3}{2})\times (-\frac{2}{3})=-1

Therefore, XY ⊥ YZ

Similarly, we can prove YZ ⊥ ZW.

Therefore, quadrilateral WXYZ is a SQUARE.

Option (1) will be the answer.

7 0
3 years ago
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