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eimsori [14]
3 years ago
13

sample of 150 Publix cashiers showed a mean hourly wage of $ 8.00, with a standard deviation of $ 1. Give an interval that is li

kely to contain about 95% of the sampled cashiers' hourly wages. A. (5, 10) B. (6, 10) C. (7, 9) D. (6, 9)
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

B. (6, 10)

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 8

Standard deviation = 1

Give an interval that is likely to contain about 95% of the sampled cashiers' hourly wages.

By the Empirical Rule, 95% of the sampled cashiers' hourly wages will be within 2 standard deviations of the mean, so from 2 standard deviations below the mean to two standard deviations above the mean

Two standard deviations below the mean:

8 - 2*1 = 6

Two standard deviations above the mean

8 + 2*1 = 10

So the correct answer is:

B. (6, 10)

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Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)
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<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

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Next, find the midpoint of (4, 1) and (2, -5):

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Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\


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Answer:

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Step-by-step explanation:

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