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Degger [83]
3 years ago
7

Which of the following correctly describes the process of inspiration (air entering the lungs).

Chemistry
1 answer:
IgorC [24]3 years ago
3 0

The lungs expand, causing their internal pressure to decrease.

Explanation:

Inhalation is one of the two mechanisms of breathing when air or oxygen is taken in.

During the process of inhalation or inspiration when air is inhaled  following changes occur:

Diaphragm gets contracted and pulls to downward attaining convex shape and the muscles in between rib ( intercostal muscles) get contracted and gets upward pull attaining the concave shape.

This contraction causes the lungs to expand and the air pressure with in gets decreased in comparison to atmospheric pressure. This results in inhalation of air into the lungs.

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Most of the elements of which region of the periodic table are located directly to the right of the metalloids?
scZoUnD [109]

Answer:

im sorry for being mean goodbye im get the real answer

Explanation:

7 0
3 years ago
How many grams of o2 are in a 5.0 mol of the oxygen gas?
allsm [11]
We are tasked to find the amount of O2 in grams given only the number of moles of oxygen gas. To solve the problem, we need first to calculate the molecular weight of oxygen. Based on the periodic table, elemental oxygen has a molecular weight of 16 g/mol. Thus its molecular weight is,
O2=16.0g/mol (2)=32 g/mol

To solve for the amount of compound oxygen in grams, we have,
O2 (g)=5 mol x 32 g/mol =160 g.

This cancel out the mols both in the numerator and denominator leaving only the g as a unit. Therefore, 5 mols of oxygen is equal to 160 g of oxygen.
4 0
3 years ago
How the proton H gradient is used to make ATP
sladkih [1.3K]

Answer:

The proton gradient produced by proton pumping during the electron transport chain is used to synthesize ATP. Protons flow down their concentration gradient into the matrix through the membrane protein ATP synthase, causing it to spin (like a water wheel) and catalyze conversion of ADP to ATP.

4 0
3 years ago
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Cr2 ] = 0.892 M and [Fe2 ] = 0.0150
Effectus [21]

<u>Given:</u>

Concentration of Cr2+ = 0.892 M

Concentration of Fe2+ = 0.0150 M

<u>To determine:</u>

The cell potential, Ecell

<u>Explanation:</u>

The half cell reactions for the given cell are:

Anode: Oxidation

Cr(s) ↔ Cr2+(aq) + 2e⁻                E⁰ = -0.91 V

Cathode: Reduction

Fe2+ (aq) + 2e⁻ ↔ Fe (s)              E⁰ = -0.44 V

------------------------------------------

Net reaction: Cr(s) + Fe2+(aq) ↔ Cr2+(aq) + Fe(s)

E°cell = E°cathode - E°anode = -0.44 - (-0.91) = 0.47 V

The cell potential can be deduced from the Nernst equation as follows:

Ecell = E°cell - (0.0591/n)log[Cr2+]/[Fe2+]

Here, n = number of electrons = 2

Ecell = 0.47 - 0.0591/2 * log[0.892]/[0.0150] = 0.418 V

Ans: The cell potential is 0.418 V

8 0
3 years ago
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What is the purpose of element tiles in the periodontic table?
son4ous [18]
It orders the chemical elements in a useful way.
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4 years ago
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