1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Volgvan
2 years ago
11

Identify the change in state that does not have an increase in entropy. a. Water evaporating b. Dry ice subliming c. Water boili

ng d. Ice melting e. Water freezing
Chemistry
1 answer:
jarptica [38.1K]2 years ago
4 0

Answer:

E. Water Freezing

Explanation:

Entropy refers to the degree of disorderliness of a system.  

A. Water Evaporating: There is an increase in entropy, this is because the phase change is from liquid to gas. Gas particles are more disordered than liquid.

B. Dry Ice sublimating: Sublimating refers to a phase change from solid to gas. This is an increase in entropy, this is because the gas particles are more disordered than solid particles

C. Water Boiling: The phase change is from liquid to gaseous state. There is an increase in entropy. Gas particles are more disordered than liquid.

D. Ice melting: The phase change is from solid to liquid state. There is an increase in entropy. Liquid particles are more disordered than that of solid.

E. Water Freezing: The phase change is from liquid to solid state. There is a decrease in entropy. solid particles are less disordered than those of liquid.

You might be interested in
What does homogeneous mixture of elements
photoshop1234 [79]

a homogeneous mixture is a mixture that appears to be one thing. for example air would be one.

3 0
3 years ago
Calculate moles of oxygen atoms in 0.68mol of KMnO4
Dominik [7]
Alright, so that means we have 0.68 mol of the compound


For each 1 mol of the compound, we have 4*1 oxygens (because there are four oxygens in the formula)
Therefore for each 0.68 mol of the compound, we have 4*0.68 moles of oxygen!
6 0
2 years ago
About 6 × 109 g of gold is thought to be dissolved in the oceans of the world. If the total volume of the oceans is 1.5 × 1021 L
Lelechka [254]

First, determine the number of moles of gold.

Number of moles  = \frac{given mass in g}{molar mass}

Given mass of gold  =6 \times 10^{9} g

Molar mass of gold  = 196.97 g/mol

Put the values,

Number of moles of gold  = \frac{6 \times 10^{9} g}{196.97 g/mol}

= 0.03046\times  10^{9} mole or 3.046\times  10^{7} moles

Now, molarity  = \frac{moles of solute}{volume of the solution in liters}

Put the values, volume of ocean  =1.5 \times 10^{21} L

Molarity = \frac{3.046\times 10^{7} moles}{1.5 \times 10^{21} L}

= 2.03\times 10^{-14} M

Thus, average molar concentration = 2.03\times 10^{-14} M




6 0
2 years ago
What is the advantage of using refrigerant identification equipment?
wlad13 [49]
So as not to mix types in a recovery system and to alert you to the presence of dangerous hydrocarbons like propane.
8 0
3 years ago
Read 2 more answers
En un balneario necesitan calentarse 1 millón de litros de agua anuales, subiendo la temperatura desde 15 ºC a 50 ºC y para ello
MAXImum [283]

Answer:

a) m_{CH_4}=2630kg

b) 1657 €

Explanation:

Hola,

a) En este problema, vamos a considerar el millón de litros de agua anuales, ya que con ellos podemos calcular el calor requerido para dicho calentamiento, sabiendo que la densidad del agua es de 1 kg/L:

Q_{H_2O}=m_{H_2O}Cp(T_2-T_1)=1x10^6LH_2O*\frac{1kgH_2O}{1LH_2O}*4.18\frac{kJ}{kg\°C}(50-15) \°C\\Q_{H_2O}=146.3x10^6kJ

Luego, usamos la entalpía de combustión del metano para calcular su requerimiento en kilogramos, sabiendo que la energía ganada por el agua, es perdida por el metano:

Q_{H_2O}=-Q_{CH_4}=-146.3x10^5kJ=m_{CH_4}\Delta _cH_{CH_4}

m_{CH_4}= \frac{Q_{CH_4}}{\Delta _cH_{CH_4}} =\frac{-146.3x10^5kJ}{-890kJ/molCH_4} *\frac{16gCH_4}{1molCH_4} \\\\m_{CH_4}=2630112.36g=2630kg

b) En este caso, consideramos que a condiciones normales de 1 bar y 273 K, 1 metro cúbico de metano cuesta 0,45 €, con esto, calculamos las moles de metano a dichas condiciones:

n_{CH_4}=\frac{PV}{RT}=\frac{1atm*1000L}{0.082\frac{atm*L}{mol*K}*273K} =44.67mol

Con ello, los kilogramos de metano que cuestan 0,45 €:

44.67molCH_4*\frac{16gCH_4}{1molCH_4}*\frac{1kg}{1000g} =0.715kgCH_4

Luego, aplicamos la regla de tres:

0.715 kg ⇒ 0.45 €

2630 kg ⇒ X

X = (2630 kg x 0.45 €) / 0.715 kg

X = 1657 €

Regards.

3 0
3 years ago
Other questions:
  • BRAINLIESTTT ASAP!! PLEASE HELP ME :)
    13·1 answer
  • The most negative electron affinity is most likely associated with which type of atoms
    13·1 answer
  • I need a data and observation for balls and how many times they bounce or whatever
    11·1 answer
  • Is water wet?with evidence
    12·2 answers
  • If 25.0 g of NH3 and 38.9g of O2 react in the following reaction, how
    5·1 answer
  • At constant pressure, which of these systems do work on the surroundings? Check all that apply.
    6·1 answer
  • A student accidentally reversed the order of solvents A, B, and C in the column chromatography and used the acetone FIRST and th
    11·1 answer
  • a 58.215 g sample of a pure metal is brought to 99.0c and added o 41.202 g of water at 21.5c in a calorimeter. if the metal and
    10·2 answers
  • If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant
    8·1 answer
  • Trình bày sự hình thành phân tử CCl4 (lai hoá sp3)
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!