The equation of the piecewise function is 
<h3>The piecewise function</h3>
On the graph, we have:
- y = 3 for all x values not more than -1
- y = -1 for all values greater than 2
Hence, the piecewise function is:
<h3>The domain of the function</h3>
This is the set of input values
In (a), we have:
x ≤ -1 and x > 2
Hence, the domain is (∞, 3] u (2, ∞)
<h3>The range of the function</h3>
This is the set of output values
In (a), we have:
f(x) = 3 and f(x) -1
Hence, the range is [3] u (-1)
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Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
(x+(x+2)+(x+4)+(x+6))=4x+12=212
x+x+x+x(2+4+6)=4x+12=212
4x (2+4+6)=4x+12=212
4x(6+6)=4x+12=212
12+4x=4x+12=212
<u>-12 -12 -12</u>
4x=4x=200
<u>/4 /4 /4</u>
<u>x=x=50</u>
<u>x=50</u>
Answer: x=4
Step-by-step explanation:
We know that line segment AC= AB + BC
we also know that AB= 3x+8 and BC= 2x-5
by substituting these, we get AC= (3x+8)+(2x-5)
AC is given as being 23, so we know that
23= (3x+8)+(2x-5)
by combining like terms, we get that
5x+3=23
simplify this to get that x=4
ρ-Value, Probability Value, or <span>Observed Level of Significance
is the definition of </span><span>any statistical test represents the probability that the results were obtained by chance alone.</span>
