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vivado [14]
3 years ago
10

Sammy is trying to determine how many triangles she can create out of a square grid that has a side of 14 inches. Use the image

below to determine the area of the triangle and how many she can cut out.
The area of the triangle is 49 in2, so she can create only 2 triangles.
The area of the triangle is 49 in2, so she can create only 4 triangles.
The area of the triangle is 98 in2, so she can create only 2 triangles.
The area of the triangle is 98 in2, so she can create only 4 triangles

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
To find the area of the triangle, you use the formula A=bh/2. This gives you the area of 49in^2 for the triangle, eliminating choices C and D. The area of the entire square is 14^2, or 196in^2, which gives us 4 when divided by the area of the triangle, 49in^2. Therefore, the answer is B, or that the area of the triangle is 49in^2 so she can create only 4 triangles.
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The point (4, -8.5) is reflected across the y axis on a coordinate plane to create a new point. What is the distance between the
Shalnov [3]

Answer:

8units

Step-by-step explanation:

If the coordinate (x,y) is reflected over the y axis, the resulting coordinate will be (-x, y)

For the coordinate (4,-8.5), the resulting point after reflection will be (-4, -8.5)

Using the distance formula;

D = √(x₂-x₁)²+(y₂-y₁)²

D = √(-8.5+8.5)²)²+(-4-4)²

D =√(-8)²

D = √64

D = 8

Hence the required distance is 8units

5 0
2 years ago
The figure below is a parallelogram. Find the measure of the<br> variables.
Ilya [14]

Answer:

B.

Step-by-step explanation:

Since 6 = 5r + 1, r = 1

As for s, if s is 2, then you can do

4 x 2 + 5 = 13 & 6 x 2 + 1 = 13

13 = 13

So B!

Hope that helps!

8 0
2 years ago
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in. Find
mr Goodwill [35]

Answer:

The volume in such a package is 27648 in³

Step-by-step explanation:

Consider the provided information.

Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.

Let the dimension are x by x by y.

Where x is the variable for the square base package and y is the variable for length.

Thus l=x, b=x and h=y

Then the volume of the box is: V(x)=x^2y (∵V=lbh)

The maximum combined length and girth is 144.

Therefore, 4x+y=144

y=144-4x

Substitute the value of y in volume of the box.

V(x)=x^2(144-4x)

V(x)=144x^2-4x^3

V'(x)=288x-12x^2

Substitute V'(x)=0.

0=288x-12x^2

12x(24-x)=0

x=0\ or\ x=24

Now apply second derivative test.

V''(x)=288-24x

V''(0)=288-24(0)>0 (Min)

V''(24)=288-24(24) (Max)

Hence, the maximum volume is at x=24

If x=24 then y=144-4(24)=48

Substituting value of x = 24 and y = 48 V(x)=x^2y gives 27648.

Hence, the volume in such a package is 27648 in³

5 0
3 years ago
In the diagram, ΔGHJ ≅ ΔSTU.
Anna007 [38]

Step-by-step explanation:

angle J is also 67 deg since the triangle is an isosceles triangle

angle T is 67 deg since the 2 triangles are congruent

angle G = 180 - 2x67 = 46 deg

ST is 5cm

HJ is 3.7cm

3 0
1 year ago
Hi everyone I really need help on number 33 and 34 I would really appreciate it
seraphim [82]
For the first one: A=pi*r^2*1/8 (1/8 becuase we are finding the area of one pane)
A=pi*16/8
A=2pi

For the second one: First do the larger circle minus the smaller circle (pretend they are whole circles)
A(larger)=pi*18^2
=324pi

A(smaller)=pi*8^2
=64pi

A=324pi-64pi =260pi

Now, a whole circle is 360 degrees so 150 degrees is 5/12 of a circle. We take 5/12 of 260pi to get the answer

260pi*5/12=340.3
7 0
3 years ago
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