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3 years ago

Solve the inequality, then identify the graph of the solution. 2x – 1 > x + 2

Mathematics

2 answers:

Anika [276]3 years ago

6 0

Answer:

$\large\boxed{x>3\to x\in(3,\ \infty)}$

Step-by-step explanation:

$2x-1>x+2\qquad\text{add 1 to both sides}\\\\2x>x+3\qquad\text{subtract x from both sides}\\\\x>3$

Blababa [14]3 years ago

4 0

Answer:

It's B on Edg.

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2 years ago

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3 years ago

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Evaluate the expression when x = 2, y = 5, and z = 4.

Stolb23 [73]

10y+x²

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3 years ago

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

6 0

3 years ago