6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer:
(e^2) (g) (g^4) (e^3)=e^b
(e)( e^2) (e)=ve^4
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
Sin(30) = LJ/8sqrt(3)
Sin 30 = ½
LJ = 4sqrt(2)
LM = JM = x
x² + x² = (4sqrt(2))²
2x² = 32
x² = 16
x = 4
Answer:
3
Step-by-step explanation:
The principal, real, root of:
![\sqrt[2]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B3%7D)
=1.73205081
All roots:
1.73205081
−1.73205081
3 is not a perfect square
I believe you cant fix one rather you need a new one. It runs about 300 plus labor
