The volume of a sphere is:
V=(4pr^3)/3 so the initial volumes is:
Vi=(4p*4.5^3)/3=121.5p in^3 (before match, approx 381.7 in^3)
Vf=(4p*4.4^3)/3=340.736p/3 (after match, approx 356.8 in^3
Vf-Vi=24.9 in^3
So the ball lost about 24.9 in^3 of air during the match...
Answer:
the first one
Step-by-step explanation:
Number of cartons taken:
ratio of cartons taken : ratio of total cartons
73 : 100
Answer:
Explanation:
The reciprocal identities
csc
θ
=
1
sin
θ
sec
θ
=
1
cos
θ
cot
θ
=
1
tan
θ
The quotient identities:
tan
θ
=
sin
θ
cos
θ
cot
θ
=
cos
θ
sin
θ
Applying all these identities, on both sides, we get:
1
sin
x
+
1
cos
x
sin
x
+
cos
x
=
cos
x
sin
x
+
sin
x
cos
x
cos
x
+
sin
x
cos
x
sin
x
sin
x
+
cos
x
=
cos
x
sin
x
+
sin
x
cos
x
1
sin
x
+
cos
x
×
cos
x
+
sin
x
cos
x
sin
x
=
cos
x
sin
x
+
sin
x
cos
x
1
cos
x
sin
x
=
cos
2
x
+
sin
2
x
sin
x
cos
x
Applying the pythagorean identity
sin
2
x
+
cos
2
x
=
1
on the right side, we get:
1
cos
x
sin
x
=
1
sin
x
cos
x
Hopefully this helps!
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