All categories

2 years ago

Solve the inequality, then identify the graph of the solution. 2x – 1 > x + 2

Mathematics

2 answers:

Anika [276]2 years ago

6 0

Answer:

$\large\boxed{x>3\to x\in(3,\ \infty)}$

Step-by-step explanation:

$2x-1>x+2\qquad\text{add 1 to both sides}\\\\2x>x+3\qquad\text{subtract x from both sides}\\\\x>3$

Blababa [14]2 years ago

4 0

Answer:

It's B on Edg.

You might be interested in

**WARNING** IF YOU ANSWER THIS QUESTION INCORRECTLY OR TRY TO ANSWER WITH FOOLISHNESS YOU WILL GET REPORTED

frozen [14]

The solution is attached as a word file.

Download doc

3 0

2 years ago

Or Simplify. Express your answer as a single term using exponents. 303*9x303*9

dmitriy555 [2]

${303}^{9} \times {303}^{9} \\ = {303}^{9 + 9} \\ = {303}^{18}$

Answer:

${303}^{18}$

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0

1 year ago

Find the number of juice boxes.

xenn [34]

Answer:

Here is the number of juice boxes

Step-by-step explanation:

No matter what source there is, you will always appear to end up finding out that there are precisely 69 juice boxes

4 0

2 years ago

I need to know what 8(ii) because I don’t know the method

Irina18 [472]

Notice y° and y° and 50°, are all three angles in a flat-line, namely "linear angles", and since a flat-line is always 180°.

$\bf y+y+50=180\implies 2y=180-50\implies 2y=130
\\\\\\
y=\cfrac{130}{2}\implies y=65$

6 0

2 years ago

Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .

stich3 [128]

$\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}$

$\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
\\\\\\
\cfrac{8^2}{7^2}\implies \cfrac{64}{49}$

4 0

2 years ago