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victus00 [196]
3 years ago
12

Can someone please help me with these questions!! Thanks,

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1

6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)

6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)

6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²

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Answer:

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Answer:

B. The variable is continuous because it is not countable.

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Step-by-step explanation:

Previous concepts

A discrete random variable "has a countable number of possible values" in a domain defined. So then the possible values for these types of random variables are the integers.

A continuous is a random variable "where the data can take infinitely many values" that means that can take values from the rational with decimals. Ans is not countable.

Solution to the problem

Let's analyze one by one the possible options:

A. The variable is discrete because it is countable.

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B. The variable is continuous because it is not countable.

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C. The variable is discrete because it is not countable.

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D. The variable is continuous because it is countable.

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