the answer should be 12. but I'm only 80% sure sooo...
1.) Equal likely chance would be 50/50 for having a dog or a cat. There are 3 possibilities: one dog and one cat, 50%, two dogs, 25%, or two cats, 25%. Adding the probabilities of having two of the same pets would theoretically give you a 50% chance.
2.) If you used two coins to simulate the possible outcome of pets the family had, you would have two fair sided coins. Each coin would have one dog side and one cat side (or heads and tails, where you would assign each pet a side of the coin).
3.) You have to do the expirament on your own.
4.) Having three pets changes the probability to a 33.3% chance of having each pet. Using number one as an example, add the probabilities to get a 66.6% chance for having three of the same pets.
5.) You can change the simulation by using a 3-sided die.
The slope:
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 8 2 ) / ( 3 - 2 ) = 6 / 1
m = 6 ( we have the same slope for AB and A`B` )
AB = √[( 3 - 2 )² + ( 8 - 2 )²] = √37
A`B` = 3.5 √37 = 21.29
3xy over 8 is the answer go to mathway
and you can find your answer and it shows you how to do it
Answer:
x = - 1/7
Step-by-step explanation:
