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taurus [48]
2 years ago
14

G wants to get over 9000 comments on his videos. He gets the same number of comments for each cat video that he uploads, and he

gets the same number of comments for each dog video that he uploads. Let C represent the number of cat videos and D represent the number of dog videos that G should upload to achieve his goal.
750C+450D>9000 According to the inequality, how many comments does each cat video get, and how many comments does each dog video get?
can G achieve his goal by uploading 8 cat videos and 7 dog videos?
Mathematics
2 answers:
defon2 years ago
4 0

Answer:

Each Cat video gets 750 comments

Each dog video gets 450 comments

Hope this helps you!

arsen [322]2 years ago
4 0

Answer:

He gets 750 comments on the cat videos and 450 on the dog videos the answer to the second question is yes

Step-by-step explanation:

khan :)

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What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]

Answer:

The Interquartile range is 10.

Step-by-step explanation:

First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.

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Hope this helps!

4 0
3 years ago
A shipment To a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 ar
riadik2000 [5.3K]

Answer:

<u>630</u> MP3 players are likely to be defective.

Step-by-step explanation:

Given:

A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.

Now, to find the MP3 players which are likely to be defective.

Let the defective MP3 players be x.

Total MP3 players = 4500.

In sample of 50 MP3 players 7 are defective.

Now, setting the proportion:

If, 50 is equivalent to 7.

Then, 4500 is equivalent to x.

Now, to solve using cross multiplication method:

\frac{50}{7} =\frac{4500}{x}

<em>By cross multiplying we get:</em>

<em />50x=31500<em />

<em>Dividing both sides by 50 we get:</em>

x=630.

Therefore, 630 MP3 players are likely to be defective.

5 0
3 years ago
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