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topjm [15]
2 years ago
10

Please answer questions 1 and/or 2, thnx

Mathematics
2 answers:
bixtya [17]2 years ago
7 0
55.79 = 0.99<em>d + </em>39.95

55.79 - 39.95 = 15.84

0.99d = 15.84

0.99d/0.99 = 15.84/0.99

d = 16

2) Equation = 12.6 million = 4(x) + 1 million
12.6 million - 1 million = 11.6 million
11.6 million/4 = x
x = 2900000

hope this helps
VMariaS [17]2 years ago
5 0
1. 39.95 + 0.99d= 55.79

0.99d=55.79-39.95
0.99d= 15.84
d= 15.84/0.99 =16

Ans = 16 DVDs

2. 12600000-1000000= 4p
 
12600000-1000000=4p
12500000=4p
p= 12500000/4
p= 3125000 or 3.125 million

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What shows the possible outcomes of a random experiment and the probability of each outcome?
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The possible outcomes of a random experiment and the probability of each outcome is called "a Probability Distribution."

<h3>What is a Probability Distribution?</h3>

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3 0
1 year ago
PLEASE HELP
enot [183]

Answer:18.9 miles

1 inch=5.4

3.5 inches =3.5×5.4

=18.9miles

hope this helps

please like and mark as brainliest

7 0
2 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
3 years ago
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