What is least perimeter of a rectangle with an area 32 square feet

1 answer:

5 0

If you have a rectangle with an area of 32 square feet, it means that the sides are
A=L x W, 32= 8*4, where
L=8, W=4
other options are
L=16, W=2 and the last one is
L=32, W=1
You need to find the least perimeter , and you know that the perimeter is P= 2(L+W)
Perimeter (1)= 2(8+4)=2*12=24
Perimeter(2)= 2(16+2)=2*18=36
Perimeter (3)=2(32+1)=2*33=66

The least perimeter is 24, with the sides L=8 and W=4

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