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Elden [556K]
2 years ago
14

Jaime wants to know how fast she can type, so she times herself as she types a paper. The paper has 429 words in it, and Jaime t

ypes it in 13 minutes. What is her typing rate, in words per minute?
Mathematics
1 answer:
JulsSmile [24]2 years ago
6 0
The answer would be 33
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Which measurement is equivalent to 6500 grams A 0.65 kg B 6.5 kg C 65 kg D 650 kg
Crazy boy [7]
B) because 1000g= 1kg
so 6500g=6.5kg
4 0
2 years ago
I NEED HELP ASAP<br><br>are the time/distance rates equivalent? ​
Art [367]
Yes because say we are doing 2/10 if you divide 2 by 2 and 10 by 2 it will be 1/5 which equals the first one so yes they are.
7 0
3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
Right triangles 1, 2,
Maru [420]

Answer:

2.2

Step-by-step explanation:

I did it on khan

4 0
3 years ago
if you know that 7 x 8=56, how can you use the commutative property of multiplication to find the product of 8 x 7 ?
Fofino [41]
Its the same thing because your just switching the order which doesn't matter when your adding or multiplying
5 0
3 years ago
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