Answer:
Hence the probability of the at least 9 of 10 in working condition is 0.3630492
Step-by-step explanation:
Given:
total transistors=100
defective=20
To Find:
P(X≥9)=P(X=9)+P(X=10)
Solution:
There are 20 defective and 80 working transistors.
Probability of at least 9 of 10 should be working out 80 working transistors
is given by,
P(X≥9)=P(X=9)+P(X=10)
<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>
P(X≥9)=
<em>(Use the permutation and combination calculator)</em>
P(X≥9)=(231900297200*20/17310309456440)
+(1646492110120/17310309456440)
P(X≥9)=0.267933+0.0951162
P(X≥9)=0.3630492
Answer:
6037.2 pounds of bamboo shoots does the female panda eat.
Step-by-step explanation:
Total pandas = 3
Total bamboo shoots eaten = 18112 pounds
Let baby panda eats bamboo = x
Male panda eats bamboo= 3x
Female panda eats bamboo = 2x
So, the equation will become
Now solving the equation to find value of x
The value of x we get : x=3018.6
So, baby panda eats bamboo shoots = 3018.6 pounds
Male panda eats bamboo shoots = 3x = 3(3018.6) = 9055.8 pounds
Female panda eats bamboo shoots = 2x = 2(3018.6)= 6037.2 pounds
So, 6037.2 pounds of bamboo shoots does the female panda eat.
Answer:
Sakura spoke for 2 minutes in Hungarian and for 3 minutes in Polish
Step-by-step explanation:
So make the variables.
Hungarian = x
Polish = y
x and y are the amount of time she spent in minutes.
x + y = 5
150x + 270 = 190y
x = 5 - y
750 - 150y + 270 = 190y
1020 = 340y
y = 3
x = 2
To find the Greatest Common Factor of 45 and 60, we do the following:
Find the Factors of 45 & 60.
45: 1, 3, 5, 9, 15, 45
60: <span>1, 2, 3, 4, 5, 6,10, 12, 15, 20, 30, 60
As you can see, 15 is the greatest common factor.</span>
Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
