You know that anything times a one is that number, so multiply 2,3, and 4, and then multiply that by one. once you get the answer, put the zeros behind each multiplied number behind your answer, and there you go.
2×3×4= 24×1=24
there are 4 zeros
240,000
The answer is two is to three
first see the common multiple of 2&4which is 4 so in end u end up with 2/4 & 3/4 hence answer is 2:3
^ ^
3*x
3*2
3x+6
5*x
5*-8
5x-40
Story short the answer is 25
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.