Question

A tank containing 64 gallons lost 6 1/4% of this through leakage how much is remaining is the tank

Answer 1

if we take 64 to be the 100%, how much is 6¼% off of it?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 64&100\\ x&6\frac{1}{4} \end{array}\implies \cfrac{64}{x}=\cfrac{100}{6\frac{1}{4}}\implies \cfrac{64}{x}=\cfrac{\frac{100}{1}}{\frac{25}{4}}\implies \cfrac{64}{x}=\cfrac{100}{1}\cdot \cfrac{4}{25} \\\\\\ \cfrac{64}{x}=16\implies 64=16x\implies \cfrac{64}{16}=x\implies 4=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{it had}}{64}-\stackrel{\textit{leakage}}{4}\implies \stackrel{\textit{remaining}}{60}$

Answer 2

Answer:

60 gallons of gas remained in the tank.

Step-by-step explanation:

1) 6 1/4 = 6.25

2) 64*6.25% = 4 OR 64*6 1/4 = 4

3) 64 - 4 = 60