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3 years ago

A tank containing 64 gallons lost 6 1/4% of this through leakage how much is remaining is the tank

Mathematics

2 answers:

jolli1 [7]3 years ago

4 0

if we take 64 to be the 100%, how much is 6¼% off of it?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 64&100\\ x&6\frac{1}{4} \end{array}\implies \cfrac{64}{x}=\cfrac{100}{6\frac{1}{4}}\implies \cfrac{64}{x}=\cfrac{\frac{100}{1}}{\frac{25}{4}}\implies \cfrac{64}{x}=\cfrac{100}{1}\cdot \cfrac{4}{25} \\\\\\ \cfrac{64}{x}=16\implies 64=16x\implies \cfrac{64}{16}=x\implies 4=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{it had}}{64}-\stackrel{\textit{leakage}}{4}\implies \stackrel{\textit{remaining}}{60}$

lilavasa [31]3 years ago

3 0

Answer:

60 gallons of gas remained in the tank.

Step-by-step explanation:

1) 6 1/4 = 6.25

2) 64*6.25% = 4 OR 64*6 1/4 = 4

3) 64 - 4 = 60

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Vesnalui [34]

Answer:

c = -4.5
z = 20
x = -12
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Step-by-step explanation:

A way to do this that will always work is ...

eliminate parenthses and collect terms
subtract any constants from the left side
subtract any variable terms from the right side
divide by the coefficient of the variable

8c -11 -6c = -2
2c -11 = -2
2c = 9
c = 4.5

3z +4 -2z -9 = 15
z -5 = 15
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30 -4x = 54 -2x
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-2x = 24
x = -12

36a -9a -5 = 6a -17
27a -5 = 6a -17
27a = 6a -12
21a = -12
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3 years ago

Elena needs to ship a 61 cm concert flute to a customer. She has two rectangular boxes. One is 25 cm by 25 cm by 50 cm. The othe

spin [16.1K]

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b) V=lwh,so, V=10cm*12cm*58cm= 6960 cm^3 shape
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Arturiano [62]

Answer:

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2 years ago

What is the volume of a cone that has a radius of 4 cm and a height of 9 cm?

vodka [1.7K]

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In this case, our base is a circle, which has a radius of 4 cm.
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We now know that our base is 16π cm.
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We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.

$V\approx3\times50.24$

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3 years ago

Read 2 more answers

Pleaseee helppp meeeeee

Alinara [238K]

I think its either A or C. Leaning more to A. Do you think you could explain the question just a bit more?

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2 years ago