given directed line segment CD, if point E divides CD three-fourths of the way from C to D, find the coordinates of E then plot
1 answer:
The coordinates of point E is (-2, -1.5)
<h3>How to determine the coordinates of point E?</h3>The complete question is added as an attachment
The given parameters are
C = (1, 6)
D = (-3, -4)
The ratio 3/4 can be represented as:
m : n = 3 : 1
So, the coordinate of point E is
E = 1/(m + n) * (mx2 + nx1, my2 + ny1)
So, we have:
E = 1/(3 + 1) * (3 * -3 + 1 * 1, 3 * -4 + 1 * 6)
Evaluate
E = 1/(4) * (-8, -6)
This gives
E = (-2, -1.5)
Hence, the coordinates of point E is (-2, -1.5)
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Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.
Answer:
The answer is below
Step-by-step explanation:
The question is not complete. The complete question is:
The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.
Solution:
Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:
sin θ = opposite / hypotenuse
Using trigonometric identities, we can get that:
sin(30) = x / 12
This gives:
0.5 = x / 12
Cross multiplying the terms to get:
x = 12 * 0.5
x = 6 ft
Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.
