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Orlov [11]
3 years ago
15

Is the statement below always,sometimes,or never true? Give at least two examples to

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0
Never true because if the product is 10 and the two numbers are 5 & 2 if you add them it won't give you 10 it will give you 7 so therefore the answer is never true
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Simplify the expression (x^3- 5x^2 + 7x - 12) ÷ (x – 4) using long division​
Kisachek [45]

Answer:

{x}^{2} - x + 3

Step-by-step explanation:

Instead, since the divisor is in the form of x - c, use what is called Synthetic Division. Remember, in this formula, -cgives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 −5 7 −12

↓ 4 −4 12

_______________

1 −1 3 0 → {x}^{2} - x + 3

You start by placing the c in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to c then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an {x}^{2}, the −1 [x] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of {x}^{2} - x + 3.

I am joyous to assist you anytime.

5 0
3 years ago
A couple of students are testing a prototype for a science project on rockets. They launch the rocket and record its height over
Illusion [34]
For this case we have the following table:
 x    f(x)
 <span><span><span>0     2
 </span><span>1     5
 </span><span>2    10
 </span><span>3     17
</span></span></span> The equation that best fits the data in the table, for this case, is given by a quadratic function.
<span><span><span> </span></span></span>The quadratic function in its standard form is:
 f (x) = x2 + 2x + 2
 Answer:
 f (x) = x2 + 2x + 2
8 0
3 years ago
Read 2 more answers
What is the slope of the line on the graph?
maxonik [38]

Answer:

Slope = 1

Step-by-step explanation:

Rise over Run= 1/1

-I hope this helps have a great night

7 0
2 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
3 years ago
What is the truth about abc ? Somebody plz help me
Natasha2012 [34]
Tick first box. It is perpendicular
Tick second box. Since it is perpendicular, it is a right angle
Tick third box, the length on two sides of a triangle is the same.
ignore the last 2 answers.
3 0
3 years ago
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