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3 years ago

14

Two Neighbors in a rural area want to know the distance between their homes in miles. What should the Neighbors use as a convers

ion factor to covert 4,224 to miles

1 answer:

lawyer [7]3 years ago

6 0

Answer:

x = 0.8 Mi

Step-by-step explanation:

for x = 4224 ft we can use the factor (1 Mi/5280 ft)

then

x = 4224 ft (1 Mi/5280 ft) = 0.8 Mi

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Ann [662]

The answer really depends on what b is. Unless you give me a number for what b equals I can’t solve it.

5 0

3 years ago

Steven has a rectangular closet the length is 10 feet and the width is 48 inches determine the area of the closet in square feet

Alexxandr [17]

To be honest with u I think that u need to multiply 10 times 48.. I think thats it not sure if is the 100% correct answer

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3 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago

Find the slope of the line

Law Incorporation [45]

Answer:

-2

Step-by-step explanation:

$y = - 2x$

the line is going down meaning its a negative and to find the slope do rise over run

4 0

2 years ago

What is the surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft? Drag and drop the co

Lera25 [3.4K]

S.A=s^2×6
S.A=7.2^2×6
S.A=311.04 ft^2 is your final answer. Hope it help!

7 0

2 years ago

Read 2 more answers