All categories

2 years ago

Simplify 3(7t-5) - 2t = 4

Mathematics

1 answer:

Inga [223]2 years ago

4 0

Answer:

Step-by-step explanation:

3(7t - 5) - 2t = 4

3*7t - 3*5 - 2t = 4

21t - 15 - 2t = 4 {combine like terms}

21t - 2t - 15 = 4

19t - 15 = 4 {Add 15 to both sides}

19t = 4 + 15

19t = 19 {Divide both sides by 19}

t = 19/19

t = 1

You might be interested in

Suppose that you put 2 dimes, 2 nickels, and 1 penny into a bag. Then you choose one coin from the bag without looking, and reco

m_a_m_a [10]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Solve, then check algebraically and graphically. 7x+14= 56

kari74 [83]

Answer:

x = 6

Step-by-step explanation:

7 x = 56-14

7 x = 42

7 x/7 to remain with x only = 42

then x = 6

6 0

2 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

2 years ago

Simplify the linear expression by subtracting,

mr Goodwill [35]

The answer is x = 1.5

8 0

2 years ago

Where is the opposite of the opposite of -1.9 situated on the number line?

SpyIntel [72]

Answer:

-1.9

Step-by-step explanation:

The opposite of the opposite is the original number, -1.9.

It is located at -1.9 on the number line.

4 0

2 years ago

Simplify 3(7t-5) - 2t = 4​

Simplify 3(7t-5) - 2t = 4