-3 + -2 = -5
-5 + 5 = 0
0 x 2 = 0
Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
1/6=16.666666...
So it is 16.6666.... to 6(or 100)
Answer:
Step-by-step explanation:
We are told that the perimeter is 48 = 2L + 2W. This reduces to
24 = L + W. Next, substitute, one by one, the 3 widths 10 cm, 3.6 cm and w cm:
a) If W = 10 cm, 24 = L + W becomes 24 = L + 10, or L = 14 cm
b) If W = 3.6 cm, 24 = L + W becomes 24 = L + 3.6, or L = 20.6 cm
c) If W = w, 24 L + W becomes 24 = L + w, so that L = (24 - w) cm
So in a proportion 23.4 over 5.49 equals 1 over o and multiply 5.49•1=23.4o
5.49=23.4o divide by 23.4 on both sides and that equals 4.26 per oz
