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vitfil [10]
3 years ago
14

Make a 10 or 100 to subtract mentally 76-59 =

Mathematics
2 answers:
Darya [45]3 years ago
6 0
I don't understand what you're saying. If you mean rounding, it would be rounded to 80-60, which would equal 20.
Nat2105 [25]3 years ago
5 0
The answer to 76-59 equals 17
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Homework ree
umka21 [38]

Answer:

325 miles and 77 dollars

Step-by-step explanation:

First, create equations. Let x equal the miles driven. The first plan expression  is 38 + 0.12x and the second plan expression is 51 + 0.08x. Setting these equal and solve for x: 38 + 0.12x = 51 + 0.08x -> 0.04x = 13 -> x = 325 miles.

The cost is found by substituting it into any of the expressions: 51 + 0.08(325) = 77 or 38 + 0.12(325) = 77

6 0
3 years ago
Algebra 2 need help on a ( ABC )
Len [333]

Answer:

b)

x =  \frac{15}{4}

Step-by-step explanation:

b) set up equations so they are equal to each other,

2x - 2 =  - 3x + 12

5x = 14

x = \frac{14}{5}

this is when f(x)=g(x) so our approximation was close.

c)solving it graphically is nearly impossible because the solution can be any value around the intersection. only way to be sure is to solve it symbolically.

3 0
3 years ago
Write the expression as the sine, cosine, or tangent of an angle.
erma4kov [3.2K]

Answer:

tan56°

Step-by-step explanation:

The Addition identity for tangent ratio is

tan(x + y) = \frac{tanx+tany}{1-tanxtany} , thus

\frac{tan24+tan32}{1-tan24tan32} = tan(24 + 32)° = tan56°

7 0
2 years ago
Could someone answer all 5 questions please
xeze [42]

Answer:

3=111

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
There are values of t so that sin t=.35 and cos t=.6
NISA [10]

Recall the fundamental rule of trig:

\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}

So, there exists an angle t such that

(0.6,0.35)=(\sin(t),\cos(t))

if and only if

\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1

Working out the numbers, we get

0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1

So, there doesn't exist a number t such that

(0.6,0.35)=(\sin(t),\cos(t))

7 0
3 years ago
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