Answer:
The measures of the angles at its corners are 
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle A
Applying the law of cosines
![cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))](https://tex.z-dn.net/?f=cos%28A%29%3D%20%5B215%5E%7B2%7D%2B125%5E%7B2%7D-185%5E%7B2%7D%5D%2F%282%28215%29%28125%29%29)
step 2
Find the measure of angle B
Applying the law of cosines
![cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))](https://tex.z-dn.net/?f=cos%28B%29%3D%20%5B215%5E%7B2%7D%2B185%5E%7B2%7D-125%5E%7B2%7D%5D%2F%282%28215%29%28185%29%29)
step 3
Find the measure of angle C
Applying the law of cosines
![cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))](https://tex.z-dn.net/?f=cos%28C%29%3D%20%5B125%5E%7B2%7D%2B185%5E%7B2%7D-215%5E%7B2%7D%5D%2F%282%28125%29%28185%29%29)
1. the last one
2.the first one hope this helps.
Answer:
x>6 that's means x is greater than 6
Y = -7x + 2
y = 9x - 14
-7x + 2 = 9x - 14
14 + 2 = 9x + 7x
16 = 16x
1 = x
y = -7x + 2
y = -7(1) + 2
y = -7 + 2
y = -5
solution is : (1,-5) <==
Answer:
-37.5 m
Step-by-step explanation:
If we assume that "one full day" is 24 hours, then 15 hours represents the fraction 15/24 of a day. Since the drilling rate was constant, and was presumed to start from a height of 0, the height after 15 hours is that fraction of the day's work:
... (15/24)×(-60 m) = -37.5 m
