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3 years ago

6= 1 - 2n + 5 How can I solve this equation

Mathematics

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

Step-by-step explanation:

Simplifying

6 = 1 + -2n + 5

Reorder the terms:

6 = 1 + 5 + -2n

Combine like terms: 1 + 5 = 6

6 = 6 + -2n

Add '-6' to each side of the equation.

6 + -6 = 6 + -6 + -2n

Combine like terms: 6 + -6 = 0

0 = 6 + -6 + -2n

Combine like terms: 6 + -6 = 0

0 = 0 + -2n

0 = -2n

Solving

0 = -2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '2n' to each side of the equation.

0 + 2n = -2n + 2n

Remove the zero:

2n = -2n + 2n

Combine like terms: -2n + 2n = 0

2n = 0

Divide each side by '2'.

n = 0

Simplifying

n = 0

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7. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point) f(g(x)) = 2 Square root of quantity two

AlladinOne [14]

Answer:

f(g(x)) =

$\sqrt{8x \: - \: 13} \: + \: 9$

Step-by-step explanation:

f(x) =

$\sqrt{x} \: + \: 9$

g(x) = 8x - 13

f(g(x) =

$\sqrt{8x \: - 13} \: + \: 9$

5 0

3 years ago

Triangle Q M N is shown. The length of Q M is 18, the length of M N is 17, and the length of Q N is 20. Law of cosines: a2 = b2

kvasek [131]

Answer:

53°

Step-by-step explanation:

17² = 18² + 20² - 2(18)(20) cos Q

289 = 324 + 400 - 720 cos Q

289 = 724 - 720 cos Q

-435 = -720 cos Q

0.6042 = cos Q

$cos^{-1} (0.6042) = Q$

Q = 52.83

3 0

3 years ago

Identify whether each set of ordered pairs is a function or is not a function. Function Not a Function

Anna35 [415]

Answer:

1. Function

2. Function

3. Function

4. Not a Function

5. Not a Function

Step-by-step explanation:

Hope it helps:)

7 0

2 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

Lif a/b =⅔ find the value of 2a²+3b²/a²+b²<br>

Contact [7]

Answer:

95/4

Step-by-step explanation:

Given,

a/b =2/3

Therefore, 2a²+3b²/a²+b² = ?

We get,

a/b = 2/3

So, we can write

a = 2 and b = 3

Now,

2×(2)² + 3×(3)²/(2)² + (3)² [Putting the values of a and b]

= 2×4 + 3×9/4 + 9

= 8 +27/4 + 9

= (32+27+36)/4 [ Taking L.C.M, we get 4]

= 95/4

4 0

2 years ago