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Reil [10]
2 years ago
5

The following question has two parts. First, answer part A. Then, answer part B.

Mathematics
2 answers:
Pie2 years ago
8 0

Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

OleMash [197]2 years ago
8 0

Answer:

Look below

Step-by-step explanation:

Part A.

Martina is correct. This is because all even numbers have 2 as a factor.

We can use 2 to find the other factor. Let's use x to represent the other factor. We can set up an equation:

2x=62

Divide both sides by 2

x=31

The missing factor is 31

Part B.

Lucas is wrong. This is because a number cannot be both prime and composite.

A prime numbers' only factors are 1 and itself

A composite number has more than 2 factors.

If 15 was both prime and composite, Lucas is contradicting himself because having 2 factors and more than 2 factors at the same time is not possible.

We can also prove him wrong because...

15: 1, 3, 5, 15

Has more than 2 factors (it has 4 factors) therefore it is composite.

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