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3 years ago

30-60-90 special right triangles

Mathematics

1 answer:

Mazyrski [523]3 years ago

6 0

So so the sides are x, x√3, 2x

here is an attachemtnt don't mind the one on the left

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Where is the function increasing?

creativ13 [48]

Hello from MrBillDoesMath!

Answer:

Increasing on the interval [-5, -2]

Discussion:

The function value remains unchanged on [-2, 1] and decreases on [1,8]

Thank you,

MrB

7 0

3 years ago

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DeAndre downloaded 8 apps onto his tablet in 12 seconds. At this rate, how many apps could he download in one minute? (12 second

ale4655 [162]

40 apps.

Explanation:
60 divided by 12 is 5. That’s how many downloading sessions could fit in a minute. Multiply 5 by the number of apps, which is 8. Your answer is 40 apps.

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2 years ago

Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
$(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)$
the expression simplifies to tan(x)sin(x)

5 0

3 years ago

Read 2 more answers

What is √49 times 7?

krek1111 [17]

Well,
First solve the square root which is 7
Funny enough, this makes 7 * 7 = 49
So the answer is 49!
Hope I helped!

8 0

3 years ago

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What is the distance between -4 and -8?

miskamm [114]

Answer: