Olivine is a mineral and gabbro is a rock
The nucleus is an organelle found in eukaryotic cells. Inside its fully enclosed nuclear membrane, it contains the majority of the cell's genetic material. This material is organized as DNA molecules, along with a variety of proteins, to form chromosomes.
Answer:
B. (The first one)
Explanation:
the only thing that is different from the two perish dishes are the temp. this is the independent variable. the dependent variable is the result. in this case, the amount of bacteria after three days
Sexual motivation for both men and women varies as a function of circulating testosterone levels.
<h3> What are hormones?</h3>
Hormones are defined as chemical substances that function as a messenger molecules in the body.
Hormones are produced in a particular part of the body and later travelled to the other parts of the body.
Testosterone is a hormone which is responsible for physical relationships and play a vital role in body. In men it plays a vital role in fat distribution, muscle mass and in the production of sperm as well as red blood cell.
Therefore,sexual motivation for both men and women varies as a function of circulating testosterone levels.
Learn more about testosterone here:
brainly.com/question/13020697
#SPJ4
Answer:
A. ![C_2=1.5\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D1.5%5Cfrac%7Bmg%7D%7BmL%7D)
B. ![C_2=0.075\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D0.075%5Cfrac%7Bmg%7D%7BmL%7D)
C. ![C_2=0.01\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D0.01%5Cfrac%7Bmg%7D%7BmL%7D)
D. ![C_2=0.001\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D0.001%5Cfrac%7Bmg%7D%7BmL%7D)
Explanation:
Hello.
In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:
![C_2=\frac{C_1V_1}{V_2}](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7BC_1V_1%7D%7BV_2%7D)
Thus, we proceed as follows:
A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.
![C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7B300%5Cmu%20L%2A5%5Cfrac%7Bmg%7D%7BmL%7D%20%7D%7B%28300%2B700%29%5Cmu%20L%7D%5C%5C%5C%5CC_2%3D1.5%5Cfrac%7Bmg%7D%7BmL%7D)
B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.
![C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7B50%5Cmu%20L%2A1.5%5Cfrac%7Bmg%7D%7BmL%7D%20%7D%7B%2850%2B450%2B500%29%5Cmu%20L%7D%5C%5C%5C%5CC_2%3D0.075%5Cfrac%7Bmg%7D%7BmL%7D)
C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.
![C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7B10%5Cmu%20L%2A1%5Cfrac%7Bmg%7D%7BmL%7D%20%7D%7B%2810%2B990%29%5Cmu%20L%7D%5C%5C%5C%5CC_2%3D0.01%5Cfrac%7Bmg%7D%7BmL%7D)
D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.
![C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}](https://tex.z-dn.net/?f=C_2%3D%5Cfrac%7B10%5Cmu%20L%2A0.1%5Cfrac%7Bmg%7D%7BmL%7D%20%7D%7B%2810%2B990%29%5Cmu%20L%7D%5C%5C%5C%5CC_2%3D0.001%5Cfrac%7Bmg%7D%7BmL%7D)
Best regards.