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ivolga24 [154]
3 years ago
6

PLEASE PLEASE HELPi don't get this and it's confusing ​

Biology
1 answer:
miv72 [106K]3 years ago
5 0
Seems pretty tough
Good luck with it
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Where does glycolysis takes place? a. mitochondrial intermembrane space b. cytosol c. mitochondrial matrix d. mitochondrial oute
zaharov [31]

Answer:

The correct answer will be option B- cytosol.

Explanation:

Glycolysis is a series of reactions which breaks down the glucose (6C molecule) to pyruvates (3C molecule).  

The reaction is the first stage of the aerobic respiration which proceeds in ten steps. The reactions take place in the "cytoplasm of the cell" of all organisms from micro-organisms to plant and animals.

Thus, Option-B is the correct answer.

7 0
4 years ago
Read 2 more answers
If a strand of DNA contains 29% adenine, then<br> how much cytosine is there?
kykrilka [37]

Answer:

it wooud have 21% cytosine

Explanation:

Adenine pairs with Thymine so there would be 29% Thymine as well, add those together and you get 58% subtract fromm 100% and you get 42% split it in half and you 21% so 21% goes to Cytosine and 21% goes to Guanine.

3 0
3 years ago
I need help with this question plzzz
Dafna11 [192]
I would think it would be C
5 0
3 years ago
Aesop's Fables is an example of which kind of drama?​
BigorU [14]

Answer:

I think it should be a folktale drama

3 0
3 years ago
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Two true-breeding stocks of pea plants are crossed. One parent has red, axial flowers and the other has white, terminal flowers;
kipiarov [429]

Answer:

Answer is 3/16.

Explanation:

If the F1 progeny has red axial flowers this shows us that red and axial genes are dominant. If we say that R is for red dominant gene, r is for white recessive gene.

If we say A is axial dominant gene, a is for terminal recessive gene.

All F1 progeny has AaRr phenotype.

When we cross them, Aa x Aa  can have AA Aa Aa aa

When Rr x Rr crossed, RR Rr Rr rr

The F2 progeny can have white axial flowers by having a and R in the phenotype with the possibility having aa= 1/4 , R in the phenotype , the possibility is 3/4.

1/4 x 3/4 = 3/16 in all F2 progeny

4 0
3 years ago
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