Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
Answer:x= 0.5,−3
Step-by-step explanation:
Answer:
= 4a + 3c + 13
Step-by-step explanation:
(9+4a)+(4+3c)
= 9 + 4a + 4 + 3c
= 4a + 3c + 13
8.8 rounding the remainder
Answer: The answer is 2,4. May I have the brainiest? pls I only need one more.
