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dalvyx [7]
3 years ago
5

Brandon says that the absolute value of a number and the opposite of a number is the same thing. Is Brandon correct? Use example

s to help you explain.
Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

No, Brandon is not correct in making that statement

Step-by-step explanation:

No, Brandon is not correct in making that statement. The absolute value of a number is the total distance between that number and 0. Brandon most likely states this because the absolute value of a negative number such as -5 would actually be the opposite, which is 5. This is not true for the absolute value of a positive such as 5, which instead is actually just 5. Meaning that the absolute value of a positive integer is the same value and NOT the opposite.

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Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy. x5y2 − x4y
il63 [147K]

Answer:

dx/dy =  (x^4 -  2x^5y -  6xy^2) /  (5x^4y^2 - 4x^3y +  2y^3).

Step-by-step explanation:

x^5y^2 − x^4y + 2xy^3 = 0

Applying the Product and Chain Rules:

y^2*5x^4*dx/dy + 2y*x^5 - (y*4x^3*dx/dy + x^4) + (y^3* 2*dx/dy + 3y^2*2x) =0

Separating the terms with derivatives:

y^2*5x^4*dx/dy - y*4x^3*dx/dy + y^3* 2*dx/dy =  x^4 -  2y*x^5 -  3y^2*2x

dx/dy =  (x^4 -  2x^5y -  6xy^2) /  (5x^4y^2 - 4x^3y +  2y^3)

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shepuryov [24]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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