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dalvyx [7]
3 years ago
5

Brandon says that the absolute value of a number and the opposite of a number is the same thing. Is Brandon correct? Use example

s to help you explain.
Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

No, Brandon is not correct in making that statement

Step-by-step explanation:

No, Brandon is not correct in making that statement. The absolute value of a number is the total distance between that number and 0. Brandon most likely states this because the absolute value of a negative number such as -5 would actually be the opposite, which is 5. This is not true for the absolute value of a positive such as 5, which instead is actually just 5. Meaning that the absolute value of a positive integer is the same value and NOT the opposite.

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How do i do this<br> 5e+4&lt;3e-6
Nonamiya [84]

Answer:

e < -5

Step-by-step explanation:

5e + 4 < 3e - 6

Subtract 3e from the right side

2e + 4 < -6

Subtract 4 from the left side

2e < -10

Divide both sides by 2

e < -5

6 0
3 years ago
Which of the following is not a fraction equivalent to 3/4 ?
Romashka-Z-Leto [24]
B. 12/18
Upon simplifying this fraction (taking a 3 out of the numerator and denominator), you end with 4/6
5 0
3 years ago
Y=-x^2-10x+24 What is the y value of the vertex?
emmasim [6.3K]

Answer:

Step-by-step explanation:

1.) Get the equation in the form y = ax^2 + bx + c.

2.) Calculate -b / 2a. This is the x-coordinate of the vertex.

3.) To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

1.) y = -x^2 - 10x + 24

2.) -(-10) / 2(-1) = -5

3.) y = -(-5)^2 - 10(-5) + 24

    y = -25 + 50 + 24

    y = 49

7 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
If the sphere shown above has a radius of 5 units, then what is the approximate volume of the sphere? (Use 3.14 for .) A. 261.67
Olenka [21]

Answer:

B. 523.33 cubic units

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

V = 4/3 (3.14) 5^3

V =523.3333333

V = 523.33 units^3

8 0
3 years ago
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