<span> here
7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8
similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4
----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>
Answer:
papá fríoStep-by-step explanation:
Answer:
x = 2 Or
x = -2
Step-by-step explanation:
Check attachment
Assuming compount interest format

for compounded per 1 year
A=future amount
P=present amount
r=rate in decimal
t=time in years
given
P=270
r=5%=0.05
the equaton is

or

for any year, 2009, is year 0, so if you wanted to input the year then

would be for t=what year it was
A.

b. 2009 to 2020
2020-2009=11 years
t=11

f(11)=461.792
about 462 cranes
A.

B. about 462
Answer:
a = 14
Step-by-step explanation:
28[-14]=14;
-14